1. Ten years ago, A was half of B in age. If the ratio of their present ages is 3:4,
what will be the total of their present ages?
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A. 45
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B. 40
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C. 35
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D. 30
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Answer : Option C
Explanation :
Let the present age of A and B be 3x and 4x respectively.
Ten years ago, P was half of Q in age
=> 3x-10 = 1
4x-10 2
=> 3x-10 = 1
4x-10 2
=>6x-20=4x-10
=>2x=10 =>x=5
=>3(5) +4(5)=15+20=35
2. Father is aged three times more than his son Sunil. After 8 years, he would be two and a
half times of Sunil's age. After further 8 years, how many times would be of Sunil's
age?
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A. 4 times
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B. 4 times
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C. 2 times
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D. 3 times
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Answer : Option C
Explanation :
Assume that Sunil's present age = x.
Then father's present age = 3x + x = 4x
After 8 years, fathers age = 2 ½ times of Sunils' age
=> (4x+8) = 2 ½ × (x+8)
=> 4x + 8 = (5/2) ×(x + 8)
=> 8x + 16 = 5x+ 40
=> 3x = 40-16 = 24
=> x = 24/3 = 8
After further 8 years,
Sunil's age = x + 8+ 8 = 8+8+8 = 24
Father's age = 4x + 8 + 8 = 4 × 8 + 8 + 8 = 48
Father's age/Sunil's age = 48/24 = 2
Then father's present age = 3x + x = 4x
After 8 years, fathers age = 2 ½ times of Sunils' age
=> (4x+8) = 2 ½ × (x+8)
=> 4x + 8 = (5/2) ×(x + 8)
=> 8x + 16 = 5x+ 40
=> 3x = 40-16 = 24
=> x = 24/3 = 8
After further 8 years,
Sunil's age = x + 8+ 8 = 8+8+8 = 24
Father's age = 4x + 8 + 8 = 4 × 8 + 8 + 8 = 48
Father's age/Sunil's age = 48/24 = 2
3. A man is 20 years older than his son. In two years, his age will be twice the age of his
son. What is the present age of his son?
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A. 23 years
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B. 18 years
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C. 21 years
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D. 20 years
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Answer : Option B
Explanation :
Let the present age of the son = x years
Then present age the man = (x+20) years
Given that in 2 years, man's age will be twice the age of his son
=>x+20 +2 = 2(x+2)
=> x = 18
Then present age the man = (x+20) years
Given that in 2 years, man's age will be twice the age of his son
=>x+20 +2 = 2(x+2)
=> x = 18
4.Present ages of jeevan and Ram are in the ratio of 5 : 4 respectively. three years hence,
the ratio of their ages will become 11 : 9 respectively. What is Ram present age in
years?
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A. 28
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B. 27
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C. 26
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D. 24
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Explanation
=> Let the present age of jeevan = 5x
Present age of Ram = 4
After 3 years, ratio of their ages = 11:9
=> (5x+3) / (4x+3) = 11/9
=> 9(5x + 3) = 11(4x + 3)
=> x = 33-27 =6
Ram's present age = 4x = 4×6 = 24
5.=> Let the present age of jeevan = 5x
Present age of Ram = 4
After 3 years, ratio of their ages = 11:9
=> (5x+3) / (4x+3) = 11/9
=> 9(5x + 3) = 11(4x + 3)
=> x = 33-27 =6
Ram's present age = 4x = 4×6 = 24
5.A is two years older than B who is twice as old as C. The total of the ages of A, B and C
is 27. How old is B?
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Answer : Option A
Explanation :
Let the age of C = x. Then
Age of B = 2x,
Age of A = 2 + 2x
=> (2+2x) + 2x + x = 27
=> 5x = 25 => 25/5 = B's age = 2x = 2×5 = 10 |
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