Quantitative Aptitude Answer with Explanation For IBPS Bank Exam

1.In what ratio must a grocer mix two varieties of pulses costing Rs. 15 and Rs. 20 per kg respectively so as to get a mixture worth Rs. 16.50 kg?
A.     3 : 7   
B.     5 : 7
C.     7 : 3   
D.     7 : 5

2.A person has 14 red socks and 14 white socks in a drawer. What is the minimum number of socks that he should take to get a correct pair?
A. 5
B.3
C.6
D.4

3.Given five concentric squares. If the area of the circle inside the smallest square is 77 square units and the distance between the corresponding corners of consecutive squares is 1.5 units, find the difference in the areas of the outermost and innermost squares
A.1254 sq units
B.1008 sq units
C.877  sq units
D.650 sq units


4.A sum of money gets doubled at 12% per annum. Then find the time?

A.7.5 years

B.8 years
C.25/3 years .

D.25/4 years

5. A can contains a mixture of two liquids A and B in the ratio 7:5 when 9 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7:9. How many litres of liquid A was contained by the can initially?

A.28 litres
B.21 litres
C.45 litres
D.36 litres

Answer
1.C 
Cost of 1 kg pulses of 1st kind                                        Cost of 1 kg pulses of 2nd kind
Rs. 15                                                                                      Rs. 20

                                                     Mean Price
                                                   Rs. 16.50

3.50                                                                                           1.50
Required rate = 3.50 : 1.50 = 7 : 3.
2.B
3.A
Here you will see that radius of the circle is equal to the diameter of the innermost square that is

πr2=77
             
r=3.5√2
              
2r=7√2

Then the diagonal of the square is 14 sq units.

Which means the diagonal of the fifth sqaure would be 14+12 units = 26.
                                                                                         
Which means the side of the fifth square would be 26√2

Therefore, the area of the fifth sqaure = 1352 sq units.

Area of the first square = 98 sq units.

Hence, the difference would be 1254 sq units.
4.C

Time= 100(n-1)/R

      =100(2-1)/12

      =100/12

      = 25/3 years

5. (B) Let initially contained 7x & 5x

So, 

         (7x-9/12*7)/(5x-9/12*5+9)=7/9

        (12x-9)/(60x+63)=1/9

         x=3

Required Quantity = 7x = 7*3=21 litres