1In a classroom there are certain number of benches.If 6 students are made to sit on a bench,then to accommodate all of them, one more bench is needed. However, if 7 students are made to sit on a bench, then after accommodating all of them, space for 5 students is left. What is the total number of students in the class
1)30 2)48 3)72 4)None of these 5)Data inadequate
2.A farmer divides his herd of cows among his four sons so that first son get one - half of the herd,the second son one-fourth, the third son one-fifth and the fourth son 7 cows. The total number of cows in the herd is :
1)100 2) 140 3)180 4)240 5)None of these
3.A circular pond whose radius is 5m amd height is 6m is cemented at Rs.25 per square meter. What is the cost of cementing the base and the curved surface area of the pond?
1).Rs.6678.55 2)Rs.6575.5 3)Rs.6950.75 4)Rs.6840.65 5)Rs.6220.75
4.Find the cost of painting all the four walls if a room 4m long,3mbroad and 6m hight at Rs.70 per sq m.
1)Rs.5600 2)Rs.5880 3)Rs.5080 4)Rs.5680 5)Rs.5780.
5.Find the side of a rhombus,one of whose diagonals measures 12m and the other 9m
1)6.5m 2)8.5m 3)7.5m 4)8m 5)None of these.
Answer
1.[3]
Let there be X benches.
Number of students = 6 (x + 1 ) ;
Number of students = (7X - 5 )
6(X + 1 ) = (7X - 5 ) => 6X + 6 = 7X - 5
X =11
Number of students = 6 (11+ 1 ) = 6*12=72
2.[2] Let the total number of cows in the herd be x
Then x/2 + x/4 + x/5 +7 = x => 10x + 5x +4x +140 = 20x
x = 140
the total number of cows = 140
3.[1] Area of the base of circular pond
= πr'2 = 22/7 * 5*5 = 78.571 m
Area of the curved surface area of circular pond
= 2πr = 2*22/7*5*6 m
= 188.571
cost of cementing the base and the curved surface = [78.57 + 188.57] * 25
= Rs.6678.55
4[2]Area of all the four walls if a room = 2(length + breadth)* height
= 2(4+3)*6 = 84
cost of painting = 70*84=Rs.5880.
5.[3] side = ½√d₁² + d₂²)
side of rhombus = 1/2 √144+81
= 1/2√225 = 1/2 * 15 =7.5m
1)30 2)48 3)72 4)None of these 5)Data inadequate
2.A farmer divides his herd of cows among his four sons so that first son get one - half of the herd,the second son one-fourth, the third son one-fifth and the fourth son 7 cows. The total number of cows in the herd is :
1)100 2) 140 3)180 4)240 5)None of these
3.A circular pond whose radius is 5m amd height is 6m is cemented at Rs.25 per square meter. What is the cost of cementing the base and the curved surface area of the pond?
1).Rs.6678.55 2)Rs.6575.5 3)Rs.6950.75 4)Rs.6840.65 5)Rs.6220.75
4.Find the cost of painting all the four walls if a room 4m long,3mbroad and 6m hight at Rs.70 per sq m.
1)Rs.5600 2)Rs.5880 3)Rs.5080 4)Rs.5680 5)Rs.5780.
5.Find the side of a rhombus,one of whose diagonals measures 12m and the other 9m
1)6.5m 2)8.5m 3)7.5m 4)8m 5)None of these.
Answer
1.[3]
Let there be X benches.
Number of students = 6 (x + 1 ) ;
Number of students = (7X - 5 )
6(X + 1 ) = (7X - 5 ) => 6X + 6 = 7X - 5
X =11
Number of students = 6 (11+ 1 ) = 6*12=72
2.[2] Let the total number of cows in the herd be x
Then x/2 + x/4 + x/5 +7 = x => 10x + 5x +4x +140 = 20x
x = 140
the total number of cows = 140
3.[1] Area of the base of circular pond
= πr'2 = 22/7 * 5*5 = 78.571 m
Area of the curved surface area of circular pond
= 2πr = 2*22/7*5*6 m
= 188.571
cost of cementing the base and the curved surface = [78.57 + 188.57] * 25
= Rs.6678.55
4[2]Area of all the four walls if a room = 2(length + breadth)* height
= 2(4+3)*6 = 84
cost of painting = 70*84=Rs.5880.
5.[3] side = ½√d₁² + d₂²)
side of rhombus = 1/2 √144+81
= 1/2√225 = 1/2 * 15 =7.5m
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