1.If the ages of P and R are added to twice the age of Q, the total becomes 59. if the ages of Qand R are added to thrice the ages of P, the total becomes 68. And if the age of P is added to the thrice the age of Q and the thrice the age of R, the total becomes 108.what is the age of P?
[1] 15 yrs [2] ] 19 yrs [3] ] 17 yrs [4] ] 12 yrs [5] None of these
2.A petrol pump owner mixed leaded and unleaded petrol in such a way that the mixture contains 10% unleaded petrol. What quantity of leaded petrol should be added to 1 ltr mixture so that the % of unleaded petrol becomes 5%?
[1] 1000ml [2]900ml [3]1900ml [4]1800ml [5] None of these
.
Answer
1.[4]
P+R+2Q = 59;
Q+R+3P= 68 AND
P+3(Q+R) = 108
solving equation , We get p= 12 yrs.
2.[1]
in 1 ltr mixture unleaded petrol.= 100 ml ...5%
leaded petrol. = 900 ml ....95%
=>100/5*95=1900
so,quantity of leaded petrol should be added = 1900-900=1000ml
3.[2]
Let original length = 100 and original breadth = 60
Then original area = 100 × 60 = 6000
⇒New length
New length = 80 and breadth = 54
[1] 15 yrs [2] ] 19 yrs [3] ] 17 yrs [4] ] 12 yrs [5] None of these
2.A petrol pump owner mixed leaded and unleaded petrol in such a way that the mixture contains 10% unleaded petrol. What quantity of leaded petrol should be added to 1 ltr mixture so that the % of unleaded petrol becomes 5%?
[1] 1000ml [2]900ml [3]1900ml [4]1800ml [5] None of these
3.A mat, when washed, lost 20% of its length and 10% of its breadth. What is the
percentage of decrease in area?
| |
[1]. 30 %
|
[2]. 28 %
|
[3]. 32 %
|
[4]. 26 %
|
4.If 204 ÷ 12.75 = 16, then 2.04 ÷ 1.275 = ?
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[1]. 16
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[2]. 1.6
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[3]. 0.16
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[4]. 0.016
|
5.7212 + 15.231 - ? = 6879
| |
[1]. 359.022
|
[2]. 362.02
|
[2]. 328.221
|
[4]. 348.231
|
Answer
1.[4]
P+R+2Q = 59;
Q+R+3P= 68 AND
P+3(Q+R) = 108
solving equation , We get p= 12 yrs.
2.[1]
in 1 ltr mixture unleaded petrol.= 100 ml ...5%
leaded petrol. = 900 ml ....95%
=>100/5*95=1900
so,quantity of leaded petrol should be added = 1900-900=1000ml
3.[2]
Let original length = 100 and original breadth = 60
Then original area = 100 × 60 = 6000
⇒New length
New length = 80 and breadth = 54
New area = 80*54=4320
Decrease in area = Original Area - New Area = 6000 - 4320 = 1680
Percentage of decrease in area = Decrease in Area/Original Area×100
=1680/6000×100=28%
4.[2]
5.[4]
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