1.The ratio between two members is 2:3. if each number is increased by 4,the ratio between them becomes 5:7The difference between the number is
[1]8 [b]6 [c]4 [d]2
2.The area of three consecutive faces of a cuboid are 12cm,20cm and 15cm, then the volume of the cuboid is :
[a]3600 [b]100 [c]80 [d]60
3.The wheel of a motor car makes 100 revolutions in moving 440m. The diameter (in meter) of wheel is :
[a] 0.44 [b]0.14 [c]0.24 [d]0.34
4. The difference between a discount of 40% on Rs 500/- and two successive discount of 36%,4% on the same amount is :
[a]Rs.0/- [b]Rs 2/- [c]Rs 1.93/- [d]Rs7.20/-
5.The sum of two numbers is 24 and their product is 143.The sum of their squares is :
[a]296 [b]295 [c]290 [d]228
Answer
[a] Let first number = 2x
second number = 3x
According to question
2x +4/3x+4 = 5/7
=>14x + 28 = 15x + 20
=> x = 8
Required difference = 3x - 2x = x = 8
2.[d]According to question,
lb = 12
bh = 20
hl = 15
lb*bh*hl = 12*20*15
=>(lbh)2 = 60cm2
3.(b)
The diameter of wheel = 440/1000*π = 440*7/1000*22
= 0.14m
4. 40% of Rs 500 = 500 * 40/100 = 200
Again, 36 % of 500 = 500 *36/100 = 180
4% of (500-180) = 320*4/100 = 12.8
Discount = 180+12.5 = Rs.192.8/-
Required difference = 200 - 192.8 = Rs.7.20/-
5.[c] Let number be x and y
According to question,
x+y = 24
xy = 143
x2 +y2 = (x+y)2 - 2xy = (24)2 - 2*143
= 290
[1]8 [b]6 [c]4 [d]2
2.The area of three consecutive faces of a cuboid are 12cm,20cm and 15cm, then the volume of the cuboid is :
[a]3600 [b]100 [c]80 [d]60
3.The wheel of a motor car makes 100 revolutions in moving 440m. The diameter (in meter) of wheel is :
[a] 0.44 [b]0.14 [c]0.24 [d]0.34
4. The difference between a discount of 40% on Rs 500/- and two successive discount of 36%,4% on the same amount is :
[a]Rs.0/- [b]Rs 2/- [c]Rs 1.93/- [d]Rs7.20/-
5.The sum of two numbers is 24 and their product is 143.The sum of their squares is :
[a]296 [b]295 [c]290 [d]228
Answer
[a] Let first number = 2x
second number = 3x
According to question
2x +4/3x+4 = 5/7
=>14x + 28 = 15x + 20
=> x = 8
Required difference = 3x - 2x = x = 8
2.[d]According to question,
lb = 12
bh = 20
hl = 15
lb*bh*hl = 12*20*15
=>(lbh)2 = 60cm2
3.(b)
The diameter of wheel = 440/1000*π = 440*7/1000*22
= 0.14m
4. 40% of Rs 500 = 500 * 40/100 = 200
Again, 36 % of 500 = 500 *36/100 = 180
4% of (500-180) = 320*4/100 = 12.8
Discount = 180+12.5 = Rs.192.8/-
Required difference = 200 - 192.8 = Rs.7.20/-
5.[c] Let number be x and y
According to question,
x+y = 24
xy = 143
x2 +y2 = (x+y)2 - 2xy = (24)2 - 2*143
= 290
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