1.The banker's discount on Rs. 1600 at 15% per annum is the same as true discount on Rs. 1680 for the same time and at the same rate. The time is:
A. 3 months
B. 4 months
C. 6 months
D. 8 months
2..A cistern 6 m long and 4 m wide contains water up to a breadth of 1 m 25 cm. Find the total area of the wet surface.
A. 42 m sqaure
B. 49 m sqaure
C. 52 m sqaure
D. 64 m sqaure
3. Richard deposits $ 5400 and got back an amount of $ 6000 after a year. Find the simple interest he got.
A. 245
B.678
C.600
D.500
4.f the price of gasoline increases by 25% and Ron intends to spend only 15% more on gasoline, by what % should he reduce the quantity of petrol that he buys?
A. 10%
B. 12.5%
C. 8%
D. 12%
5.P can lay railway track between two stations in 16 days. Q can do the same job in 12 days. With the help of R, they completes the job in 4 days. How much days does it take for R alone to complete the work?
A. 9(3/5) days
B. 9(1/5) days
C. 9(2/5) days
D. 10 days
Answer
1.b
S.I. on Rs. 1600 = T.D. on Rs. 1680.
Rs. 1600 is the P.W. of Rs. 1680, i.e., Rs. 80 is on Rs. 1600 at 15%.
Time = 100 x 80 year = 1 year = 4 months.
1600 x 15 3
2.B
Area of the wet surface =
2[lb+bh+hl] - lb = 2 [bh+hl] + lb
= 2[(4*1.25+6*1.25)]+6*4 = 49 m square
3.CPrincipal (P) = $ 5400,
Amount (A) = $ 6000
Simple Interest (SI) = Amount (A) – Principal (P)
= 6000 - 5400
= 600
Therefore, Richard got an interest of $ 600
4c
,Let the price of 1 litre of gasoline be $x and let Ron initially buy 'y' litres of gasoline.
Therefore, he would have spent $xy on gasoline.
When the price of gasoline increases by 25%, the new price per litre of gasoline is 1.25x.
Ron intends to increase the amount he spends on gasoline by 15%.
i.e., he is willing to spend xy + 15% of xy = 1.15xy
Let the new quantity of gasoline that he can get be 'q'.
Then, 1.25x * q =
1.15xy/1.25x = 1.15/1.25 y = 0.92y.
As the new quantity that he can buy is 0.92y, he gets 0.08y lesser than what he used to get earlier.
Or a reduction of 8%.
5.a
Amount of work P can do in 1 day = 1/16
Amount of work Q can do in 1 day = 1/12
Amount of work P, Q and R can together do in 1 day = 1/4
Amount of work R can do in 1 day = 1/4 - (1/16 + 1/12) = 3/16 – 1/12 = 5/48
=> Hence R can do the job on 48/5 days = 9 (3/5) days
A. 3 months
B. 4 months
C. 6 months
D. 8 months
2..A cistern 6 m long and 4 m wide contains water up to a breadth of 1 m 25 cm. Find the total area of the wet surface.
A. 42 m sqaure
B. 49 m sqaure
C. 52 m sqaure
D. 64 m sqaure
3. Richard deposits $ 5400 and got back an amount of $ 6000 after a year. Find the simple interest he got.
A. 245
B.678
C.600
D.500
4.f the price of gasoline increases by 25% and Ron intends to spend only 15% more on gasoline, by what % should he reduce the quantity of petrol that he buys?
A. 10%
B. 12.5%
C. 8%
D. 12%
5.P can lay railway track between two stations in 16 days. Q can do the same job in 12 days. With the help of R, they completes the job in 4 days. How much days does it take for R alone to complete the work?
A. 9(3/5) days
B. 9(1/5) days
C. 9(2/5) days
D. 10 days
Answer
1.b
S.I. on Rs. 1600 = T.D. on Rs. 1680.
Rs. 1600 is the P.W. of Rs. 1680, i.e., Rs. 80 is on Rs. 1600 at 15%.
Time = 100 x 80 year = 1 year = 4 months.
1600 x 15 3
2.B
Area of the wet surface =
2[lb+bh+hl] - lb = 2 [bh+hl] + lb
= 2[(4*1.25+6*1.25)]+6*4 = 49 m square
3.CPrincipal (P) = $ 5400,
Amount (A) = $ 6000
Simple Interest (SI) = Amount (A) – Principal (P)
= 6000 - 5400
= 600
Therefore, Richard got an interest of $ 600
4c
,Let the price of 1 litre of gasoline be $x and let Ron initially buy 'y' litres of gasoline.
Therefore, he would have spent $xy on gasoline.
When the price of gasoline increases by 25%, the new price per litre of gasoline is 1.25x.
Ron intends to increase the amount he spends on gasoline by 15%.
i.e., he is willing to spend xy + 15% of xy = 1.15xy
Let the new quantity of gasoline that he can get be 'q'.
Then, 1.25x * q =
1.15xy/1.25x = 1.15/1.25 y = 0.92y.
As the new quantity that he can buy is 0.92y, he gets 0.08y lesser than what he used to get earlier.
Or a reduction of 8%.
5.a
Amount of work P can do in 1 day = 1/16
Amount of work Q can do in 1 day = 1/12
Amount of work P, Q and R can together do in 1 day = 1/4
Amount of work R can do in 1 day = 1/4 - (1/16 + 1/12) = 3/16 – 1/12 = 5/48
=> Hence R can do the job on 48/5 days = 9 (3/5) days
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